helloxielan 2014-10-03 14:56 采纳率: 0%
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AJAX URL问题…很奇怪

I have a page from which I am trying to make an AJAX call, but it isn't working, and I'm stumped as to why. My call is:

$.ajax({
    type: "GET",
    url: "<relative URL>/index.php?action=x",
    dataType: "JSON"
}).success(function(person) {
    alert(person.name) //alerts naem
});
    return false;
});

and the PHP is:

<? 

if($_GET["action"] == "x"){

    $person = array("name"=>"Jon Doe","Reputation"=>"Good");
    header("Content-Type: application/json");
    echo json_encode($person);
}

?>

I don't THINK the issue is a faulty URL, since it is a c/p of working calls. It seems to me (but I'm not sure) that it chooses to reuse the old 'action-values' from when the source page was loaded originally. For some reason it completely ignores my action-value…?

Any ideas?

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3条回答 默认 最新

  • weixin_33690963 2014-10-03 15:10
    关注

    Try moving the PHP into its own file rather than the index.php, which I assume is your main PHP file.

    $.ajax({
    type: "GET",
    url: "/ajax.php?action=x",
    dataType: "JSON",
    success: function (person) {
       console.log(person.name);
    }
});

    This should be a separate file. Call it ajax.php for an example.

    <? 
// ajax.php
if($_GET["action"] == "x"){

    $person = array("name"=>"Jon Doe","Reputation"=>"Good");
    die(json_encode($person));
}

?>

    Just make sure ajax.php is in the route of your project and this should work. Check the console.log if it doesn't.

    评论
  • weixin_33709219 2014-10-03 15:34
    关注

    Try moving the variable into 'data': 

    $.ajax({
    type: "GET",
    url: "<relative URL>/index.php", 
    data: "action=x",
    success: function (person) {
       console.log(person.name);
    }
});
    评论
  • 乱世＠小熊 2014-10-03 17:32
    关注

    Since you are calling index.php with a get parameter, you might be echoing the json_encode and then continuing to output everything else after the if statement.

    Try this?

    <? 

if($_GET["action"] == "x"){

    $person = array("name"=>"Jon Doe","Reputation"=>"Good");
    header("Content-Type: application/json");
    echo json_encode($person);
    exit;

}

?>

    I'm assuming you have more content in the index.php below that if statement. If so, the exit; statement would be needed so that you only echo the json and not anything after the if statement.

    The ajax response can be viewed in Google Chrome's Dev Tools, under the Network tab.

    Let's say you had no exit; statement:

    <? 

if($_GET["action"] == "x"){

    $person = array("name"=>"Jon Doe","Reputation"=>"Good");
    header("Content-Type: application/json");
    echo json_encode($person);

}

?>

<html>
<head></head>
<body>
...etc, etc

    The ajax response under Dev tools would look something like this:

    {"name":"Jon Doe","Reputation":"Good"}<html><head></head><body>... and so on

    which would then try to be parsed by the $.ajax into a JSON object.

    But this is not possible because <html><head></head><body>... is not valid JSON.

    Hope this helps!

    评论

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