weixin_33712881 2017-10-16 09:08 采纳率: 0%
浏览 35

控制台日志JSON结果

I'm just starting to learn about APIs, JSON, and Jquery and I am stuck. How would I console log the following from my Jquery call -

name: "The Old Mill Cafe"

Here's my current code:

$(document).ready(function(){
  $("#mainbutton").on("click", function() {
    $.ajax({
      url: "https://developers.zomato.com/api/v2.1/search?entity_id=Chicago%2C%20IL%20&entity_type=city",
      headers: {
        "X-Zomato-API-Key": "…"
      },
      method: "GET"
    }).done(function(data) {
      console.log(data);
    });
  });
});
  • 写回答

2条回答 默认 最新

  • weixin_33691598 2017-10-16 09:12
    关注

    Your console.log is telling you that data is an object with a property called restaurants which is an array with a single entry. That entry is an object with a property called restaurant which is an object with a property called name. So:

    console.log(data.restaurants[0].restaurant.name);
    
    评论

报告相同问题?

悬赏问题

  • ¥15 如何让企业微信机器人实现消息汇总整合
  • ¥50 关于#ui#的问题:做yolov8的ui界面出现的问题
  • ¥15 如何用Python爬取各高校教师公开的教育和工作经历
  • ¥15 TLE9879QXA40 电机驱动
  • ¥20 对于工程问题的非线性数学模型进行线性化
  • ¥15 Mirare PLUS 进行密钥认证?(详解)
  • ¥15 物体双站RCS和其组成阵列后的双站RCS关系验证
  • ¥20 想用ollama做一个自己的AI数据库
  • ¥15 关于qualoth编辑及缝合服装领子的问题解决方案探寻
  • ¥15 请问怎么才能复现这样的图呀