weixin_33744141 2013-11-22 06:17 采纳率: 0%
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jQuery Ajax返回错误

I am using this ajax function

function testfunction(ttl){

        jQuery.ajax({url:"",
           type: "POST",
           data: { 'action_sub':'Load_twittercontact'},
           success:function(res){

                  //Do something

         },error:function(e){
                console.log(e.error);

        }});
    }

After some time , i got a error in error conolse. This is the error

function (){if(!d){var c=arguments,g,h,i,j,k;b&&(k=b,b=0);for(g=0,h=c.length;g<h;g++)i=c[g],j=f.type(i),j==="array"?e.done.apply(e,i):j==="function"&&a.push(i);k&&e.resolveWith(k[0],k[1])}return this} 

How to solve this issue ?

  • 写回答

1条回答 默认 最新

  • weixin_33698823 2013-11-22 06:45
    关注

    Your error handler definition should be like the following code:

    error: function(requestObject, error, errorThrown) { }
    

    And to know what exactly happened, you should log the error parameter, like the following code:

    error: function(requestObject, error, errorThrown) {

         console.log(error);
    

    }

    Hope this helps.

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