weixin_33713503 2015-11-06 12:19 采纳率: 0%
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期望AJAX中的json数组

How is it possible for me to get my Ajax to expect my array within my success. Currently I presume I use a flat object and this needs to grab all the data passed back to the client side so I can update my notifications.

I presume everything else is correct!

    {"num":1,"670":{"notification_id":"670","notification_content":"
    Lucy  Botham posted a status on your
    wall","notification_throughurl":"singlepoststreamitem.php?
    streamitem_id=545","notification_triggeredby"
    "85","notification_status":"1"},"671":
    {"notification_id":"671","notification_content":"Lucy  Botham
    posted a status on your 
    wall","notification_throughurl":"singlepoststreamitem.php?streamitem_id=546"
   ,"notification_triggeredby":"85","notification_status":"1"}}

SERVER SIDE

while($row = mysqli_fetch_assoc($com)){
    $id = $row['notification_id'];
    $num = mysqli_num_rows($com);
    if($num){
        $json['num'] = 1;
    }else{
        $json['num'] = 0;
    }
    $json[$id]['notification_id'] = $row['notification_id'];
    $json[$id]['notification_content'] = $row['notification_content'];
    $json[$id]['notification_throughurl'] = $row['notification_throughurl'];
    $json[$id]['notification_triggeredby'] = $row['notification_triggeredby'];
    $json[$id]['notification_status'] = $row['notification_status'];
}
echo json_encode($json);

CLIENT

        function loadIt() {
        $.ajax({
        type: "GET",
        url: "viewajax.php?    
        notification_id="+notification_id+"
        &notification_targetuser="+notification_targetuser+
       "&notification_triggeredby="+notification_triggeredby,   
       dataType:"json",
       success: function(data){
       //do something 
       )
  • 写回答

1条回答 默认 最新

  • bug^君 2015-11-06 12:20
    关注

    use json.parse()

    success: function(data){
         var a = JSON.parse(data);
         //loop var a to get your data 
    }
    

    See this link, you might get some idea.

    评论

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