我需要提交每一行代码,但它只实际上只提交了第一行。无论怎么单击Submit按钮,它都只执行该特定行......我该怎么解决这个问题?
// my form :
<form action="">
<table class="table table-hover table-centered m-0 table-bordered">
<thead>
<tr>
<th>Name</th>
<th>Designation</th>
<th>Account Number</th>
<th>Attendance</th>
<th>Rate</th>
<th>Loan </th>
<th>Action</th>
</tr>
</thead>
<tbody id="salaryData">
</tbody>
</table>
</form>
下面的代码显示了从数据库中获取的数据,并且这个数据插入到了tbody,tbody id是#salaryData:
success: function(data) {
// alert('test');
var html = '';
var i;
for (i = 0; i < data.length; i++) {
html += '<tr>' +
'<td>' + data[i].emp_name + ' </td>' +
'<td>' + data[i].cat_name + '</td>' +
'<td>' + data[i].emp_account_number + '</td>' +
'<td>' +
'<input type="text" class="form-control" id="attendance" name="attendance" placeholder="Attendance" required>' +
'</td>' +
'<td>1</td>' +
'<td>' +
'<input type="text" class="form-control" id="loan" name="loan" placeholder="Loan" required>' +
'</td>' +
'<td>' +
'<a href="javascript:;" class="btn btn-primary item-edit" id="btnSave">Submit</a>' +
'</td>' +
'</tr>';
}
$('#salaryData').html(html);
// submit code
$(function() {
$('#salaryData').on('click', '.item-edit', function() {
var row = $(this).closest("tr")
var attendance = row.find("[name=attendance]").val();
var loan = row.find("[name=loan]").val();
$.ajax({
type : "POST",
url : "<?php echo site_url('con_salary/testSalary')?>",
dataType : "JSON",
data : {attendance:attendance , loan:loan},
success: function(data){
if(data==1 ){
$('#btnSave').prop('disabled', false);
}
else{
$('#btnSave').prop('disabled', true);
}
}
});
return false;
});
});