定义一个CMP3类，其有一个构造函数和公有函数Play。

Question

定义一个CMP3类，其有一个构造函数和公有函数Play；定义一个Phone类，其有一个构造函数和一个公有函数Call；再定义一个CMp3Phone类，其是由CMP3类和Phone类派生而来。用main函数测试基类构造函数的执行顺序以及访问基类的成员函数。

Answer 1

#include<iostream>
using namespace std;
class CMP3{
public:
    CMP3(){
        std::cout << "this is CMP3" << std::endl;
    }

    void Play(){
        std::cout << "CMP3::Play()" << std::endl;
    }
};

class Phone{
 public:
    Phone(){
        std::cout << "this is Phone" << std::endl;
    }

    void Call(){
        std::cout << "Phone::Call()" << std::endl;
    }
};

class CMp3Phone:public CMP3,public Phone{
public:
    CMp3Phone() {
        std::cout << "this is CMp3Phone" << std::endl;
    }
};

int main()
{
    CMp3Phone *mp3Phone = new CMp3Phone();
    mp3Phone->Play();
    mp3Phone->Call();
    return 0;
}