我有一个返回对象的webMethod,访问从jQueryAjax方法返回的对象有困难。我想访问HighlightResult并在中继器中显示,但一直收到错误:处理请求时出错,内部服务器错误。
我的目标是:
public class SearchResults
{
internal SearchResults()
{
}
public virtual IQueryable<Document> DocumentResults { get; internal set; }
public virtual IQueryable<Page> PageResults { get; internal set; }
public virtual IQueryable<Word> WordResults { get; internal set; }
public ICollection<String> HighlightResults { get; internal set; }
public int QueryTime { get; internal set; }
public int TotalResults { get; internal set; }
}
我的Ajax函数:
var query = String($('[id$=txtSearch]').val());
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "Viewer.aspx/GetHighlightResults",
dataType: "json",
data: JSON.stringify({docID: docid, query: query,
pageNumber: 1, resultsPerPage: 10}),
success: function (response) {
alert("Success!!");
var data = response.d;
// none of these are displaying....
alert(String(data));
alert(String(data.HighlightResults));
alert(String(data.HighlightResults[0]));
$.each(data, function(index, item) {
alert(item);
alert(item.HighlightResults);
$("#search-results").append("<b>" + item + "</b>");
})
},
error: function (xhr, status, error) {
alert("responseText=" + xhr.responseText +
"
textStatus=" + status + "
errorThrown=" + error);
}
});
我的网络方法:
[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
public static SearchResults GetHighlightResults(String docID, String query,
String pageNumber, String resultsPerPage)
{
SearchResults results = null;
try
{
ArchiveSearcher searcher = new ArchiveSearcher();
if (!String.IsNullOrEmpty(query) && Convert.ToInt32(docID) > 0 &&
Convert.ToInt32(pageNumber) > 0 && Convert.ToInt32(resultsPerPage) > 0)
{
results = searcher.SearchDocument(Convert.ToInt32(docID), query,
Convert.ToInt32(pageNumber), Convert.ToInt32(resultsPerPage));
}
}
catch (Exception ex)
{
// Log the exception.
ArchiveViewer.Logic.ExceptionUtility.LogException(ex, "GetSearchResults in Viewer.aspx.cs");
}
return results;
}
任何帮助都将不胜感激!
EDIT: 如果我从Web方法返回ICollection<String> Highlight结果,则可以使用以下方法从jquery ajax函数访问它:
success: function (response) {
var data = response.d;
$.each(data, function(index, item) {
alert(item);
....
我认为我的问题与我如何访问整个SearchResults对象有关。 我已经注释掉了Ajax函数中的所有内容,但它仍然失败。