如何在ajax语句中传递多个值？

Question

有人可以帮助我吗？ 我收到此错误：

"Notice: Undefined index: name in C:\xampp\htdocs\test.php on line 2

我想知道如何在ajax语句中传递多个值，例如：

data: {name: "john", country: "UK"}

在服务器端检索它，最后将其发布回初始页面。

客户端：

<script>
    $(document).ready(function(){

        $("#btn").click(function(){

            $.ajax({
                type: "POST",
                url: "test.php",
                data: {name: "John"}
            })

            .done(function() {
                $("#output").load("test.php");
           });
        });

     });
 </script>


<form>
    <input type="button" value="Test" id="btn" />
</form>

<div id="output"> </div>

服务器端：

<?php
    $student =(string) $_POST['name']; 
    //$student = isset($_POST['name'])?$_POST['name']:'err';
    $message = "Name: ".$student;
    echo ($message);
?>

Answer 1

You are loading the test.php file twice: Once with your POST request, which returns the correct data... but then you are ignoring that data and requesting it again with a GET request, which of course has no POSTdata attached.

Try:

.done(function(data) {
    $("#output").html(data);
});