jQuery AJax结果回显PHP

Question

I must to check the result of Ajax are same with some PHP variable value. Is there anyway to do this?

Thank you in advance for help.

My Ajax HTML:

<?php
$x = '<p id="ip"></p>';
$y = '2_2_1_3';

if($x == $y){
  echo $x;
}
?>

<a id="input" href="#">Get value<input type="hidden" value="2_2_1_3"></a>

<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
<script>
jQuery(document).ready(function(){
  $("#input").on("click", function(){
    $.ajax({
      type: 'POST',
      url: "ip2.php", 
      data:'ip=' + $(this).parent().find('input').val(),
      success: function(data){
      $("#ip").html(data);
      }
    });
  });
});
</script>

The PHP script:

<?php
if($_POST['ip'] >= 0){
  $ip = $_POST['ip'];  
  echo $ip;  
}
?>

Answer 1

I'm not entirely sure what you want to do, but you can always send your post data as an object in javascript, for simplicity you can use the post function.

Example:

    $.post( "ip2.php", { ip: $(this).parent().find('input').val() }, function( data ) {
      console.log( data );
    });

More info: https://api.jquery.com/jquery.post/ https://api.jquery.com/jQuery.ajax/