Ajax脚本中的语法错误

Question

I'm having a hard time arranging my ajax script very well and i thinking if i could help some help here

$(document).ready(function() {
      $follow_container = $('#follow_container');
      var follow = localStorage.getItem('follow');
      if (follow !== null) {
        $follow_container.html(follow).show()
      }
      $('.followclick').on('click', function(event) {
            if (follow == null) {
              $('#follow_container').load('http://mysite/news.asp', function() {
                  localStorage.setItem('follow', $follow_container.html());
                }
              });

Answer 1

Every time you open a block of code (using a {), you also have to close it. Every time you open a function call (using a (), you also have to close it. You code just sort of trails off without actually closing anything.

When you do this:

if (follow == null) {

Somewhere, later in the code, at the end of that if block, you need to do this:

}

When you do this:

on(

Somewhere, later, you need to do this:

)

So, putting all of that together... close your code blocks:

$(document).ready(function() {
    $follow_container = $('#follow_container');
    var follow = localStorage.getItem('follow');
    if (follow !== null) {
        $follow_container.html(follow).show()
    }
    $('.followclick').on('click', function(event) {
        if (follow == null) {
            $('#follow_container').load('http://mysite/news.asp', function() {
                localStorage.setItem('follow', $follow_container.html());
            });
        }
    });
});