Toast 信息参数的问题

Question

我想在一个静态类中显示一个toast信息，但是Toast信息参数传递应用程序的内容时有问题。请问如何在一个静态类中显示一个toast信息？
附上我的部分代码：

 public class MainActivity extends Activity {
         public void onCreate(Bundle savedInstanceState) {
                super.onCreate(savedInstanceState);
                setContentView(R.layout.training_four_position);
            mEndlessRunnable = (Runnable) new UpdateRunnable();
            mEndlessRunnable.run();
    }


   private static class UpdateRunnable implements Runnable  {
   private int mState; 

   public UpdateRunnable(Handler handler, Button[] buttons) {
         mHandler = handler;
         mButtons = buttons;
   }

    public void run() {
        switch (mState) {
        case 0:
               mState = 1;
               break;
        case 1:

            mState = 0;
               // Here is the issue in my toast message
               Toast.makeText(CONTEXT, "Toast message.",Toast.LENGTH_LONG).show();
                break;
     }

  mHandler.postDelayed(this,1000)); 

  }// End of run()
  }//End of class UpdateRunnable
  } //End of MainActivity

Answer 1

你可以为toast创建一个单独的方法

public void showToast(String message){

    Toast.makeText(getApplicationContext(), message, Toast.LENGTH_SHORT).show();

}//end showToast