求2个C语言代码，高价悬赏

Question

Answer 1

问题解决的话，请点下采纳

#include <stdio.h>

void printRange(char a, char b)
{
    printf("Range(%c to %c) : ", a, b);
    if (a < b)
    {
        for (char i = a; i <= b; i++)
            printf("%c ", i);
    }
    else
    {
        for (char i = a; i >= b; i--)
            printf("%c ", i);
    }
    printf("\n");
}

void printRangeStep(char a, char b, int n)
{
    printf("Range(%c to %c) Step %d: ", a, b, n);
    if (a < b)
    {
        for (char i = a; i <= b; i+=n)
            printf("%c ", i);
    }
    else
    {
        for (char i = a; i >= b; i-=n)
            printf("%c ", i);
    }
    printf("\n");
}

int main()
{
    printRange('a','x');
    printRange('q','b');
    printRangeStep('c','z',3);
    return 0;
}

#include <stdio.h>
int main()
{
    char * myString = "hope cheer courage";
    char vowel[6] = "aeiou";
    int count = 0;
    for (int i = 0; myString[i]; i++)
    {
        int f = 0;
        for (int j = 0; j < 5; j++)
        {
            if (vowel[j] == myString[i])
            {
                f = 1;
                count++;
                break;
            }
        }
        if (!f)
            printf("%c\n", myString[i]);
        else
            printf("%c - vowel\n", myString[i]);
    }
    printf("Total number of vowels: %d.\n", count);
    return 0;
}

问题解决的话，请点下采纳