weixin_33711647 2013-12-06 10:14 采纳率: 0%
浏览 37

成功功能无警报

I am trying to insert value in database from jquery ajax and i want whenever data insertion is successfull, a result output comes true other wise "error:failed". My entry in database successfully updated, but when i alert(msg), its doesnt give me message.

          <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js">    </script>
  <body>
    <div class="wrapper">
    <div id="main" style="padding:50px 0 0 0;">
         <!-- Form -->
       <form id="contact-form"  method="post">
        <h3>Paypal Payment Details</h3>
        <div class="controls">
            <label>
                <span>TagId</span>
                <input placeholder="Please enter TagId" id="tagid" type="text" tabindex="1" >
            </label>
        </div>
        <div class="controls">
            <label>
                <span>Paypal Email: (required)</span>
                <input placeholder="All Payment will be collected in this email address" id="email" type="email" tabindex="2">
            </label>
        </div>
        <div class="controls">
            <label>
                <span>Amount</span>
                <input placeholder="Amount you would like to charged in GBP" id="amount" type="tel" tabindex="3">
            </label>
        </div>
                    <div class="controls">
                 <div id="error_div"></div>
                 </div>
        <div>
<button name="submit" type="submit" id="form-submit">Submit Detail</button>
        </div>
    </form>
    <!-- /Form -->

    </div>
</div>
 <script type="text/javascript">
        $(document).ready(function(){
   $('#form-submit').click(function()
    {
    var tagid = $("#tagid").val();
var email = $("#email").val();
var amount = $("#amount").val();
var param = 'tagid='+ tagid + '&email=' + email + '&amount=' + amount;
    param = param + '&type=assign_amount';
    locurl = 'dbentry.php';
          $.ajax({
              url: locurl,
              type:'post',
              data:param,
              success:function(msg)
                {  
                    alert(msg);            
                }
              });
});
  });

dbentry.php

  <?php
$vals = $_POST;
    include 'dbconfig.php';

    if($vals['type'] == "assign_amount")
{
    $values = assign_amount();  
    echo json_encode(array('status' =>$values));    
}


function assign_amount()
{
    global $con;
    global $vals;
    $sql = "INSERT INTO `dynamic_url`(`tagid`,`email`,`amount`) VALUES('".$vals['tagid']."','".$vals['email']."','".$vals['amount']."')";
    $result = mysql_query($sql,$con);
            if($result){
                if( mysql_affected_rows() > 0 ){
                    $status="success";
                }
            }else{
                $status="failed";
            }
            return $status;
}


  ?>
  • 写回答

5条回答 默认 最新

  • weixin_33701617 2013-12-06 10:15
    关注

    Try to echo it like

    if($result){
        if( mysql_affected_rows() > 0 ){
            $status="success";
        }
    } else {
        $status="failed";
    }
    return $status;
    

    And in your if statement code like

    if($vals['type'] == "assign_amount")
    {
        $values = assign_amount();  
        echo $values;
    }
    

    For the ajax return purpose you better to echo or print rather than return it.

    评论

报告相同问题?

悬赏问题

  • ¥15 完成下列问题完成下列问题
  • ¥15 C#算法问题, 不知道怎么处理这个数据的转换
  • ¥15 YoloV5 第三方库的版本对照问题
  • ¥15 请完成下列相关问题!
  • ¥15 drone 推送镜像时候 purge: true 推送完毕后没有删除对应的镜像,手动拷贝到服务器执行结果正确在样才能让指令自动执行成功删除对应镜像,如何解决?
  • ¥15 求daily translation(DT)偏差订正方法的代码
  • ¥15 js调用html页面需要隐藏某个按钮
  • ¥15 ads仿真结果在圆图上是怎么读数的
  • ¥20 Cotex M3的调试和程序执行方式是什么样的?
  • ¥20 java项目连接sqlserver时报ssl相关错误