声明一个Shape抽象类,在此基础上派生出Rectangle(矩形)和Circle(圆)类;
二者都有GetArea( )函数计算对象的面积,GetPerim( )函数计算对象的周长。
要求:请使用基类引用调用虚函数方法,实现动态多态
有大佬帮忙看看这个怎么写吗
- 写回答
- 好问题 0 提建议
- 关注问题
- 邀请回答
-
1条回答 默认 最新
qtchen_1988 2020-06-15 18:58关注#include <iostream> #define _USE_MATH_DEFINES #include <math.h> using namespace std; class Shape{ public: virtual double GetArea()=0; virtual double GetPerim()=0; }; class Rectangle:public Shape{ public: Rectangle(double length,double width):mLength(length),mWidth(width){} virtual double GetArea(){ return mLength*mWidth; } virtual double GetPerim(){ return (mLength+mWidth)*2; } private: double mLength; double mWidth; }; class Circle:public Shape{ public: Circle(double r):mR(r){} virtual double GetArea(){ return M_PI*mR*mR; } virtual double GetPerim(){ return mR*2*M_PI; } private: double mR; }; int main() { Rectangle rect(12.8,6); Circle cle(4.5); Shape *sh = ▭ std::cout<<sh->GetArea()<<std::endl; std::cout<<sh->GetPerim()<<std::endl; std::cout<<"***************************"<<std::endl; sh = &cle; std::cout<<sh->GetArea()<<std::endl; std::cout<<sh->GetPerim()<<std::endl; return 0; }本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报