weixin_33696106 2012-09-24 13:05 采纳率: 0%
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无法计算出ajax responsetext

I am new to web development and am trying to write simple code that changes visibility of an HTML element using JavaScript and AJAX, but my code is not working.

The PHP script I'm running is simple:

    <?php
     echo TRUE;
    ?>

The JavaScript code is:

function getuname() {
  //create_xmlhttpobj();
  var userName = document.getElementById('uName');

  var url = "http://localhost/test.php";
  //script that returns whether username exisits or not

  request.open("GET", url, true);
  request.send(null);
  request.onreadystatechange = updatepage();
  //alert(userName.value);
}

function updatepage() {
  //alert(request.readyState);
  alert(request.readyState);
  //alert(request.responseText);
  if (request.readyState == 4) {
    alert('here123');
    togvis();
  }
}

The statement alert(request.responseText); shows a blank alert box.

Can someone tell me what I might be doing wrong?

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1条回答 默认 最新

  • weixin_33713707 2012-09-24 13:05
    关注

    You are calling the function updatepage, not assigning it.

    request.onreadystatechange = updatepage();
    

    needs to be

    request.onreadystatechange = updatepage;
    
    评论

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