weixin_33709364 2013-11-18 02:37 采纳率: 0%
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jQuery / AJAX&PHP域检查器

I'm trying to build a domain availability checker.

My PHP code is the following:

<?php

$domain = $_GET["domname"];

function get_data($url) {
    $ch = curl_init();
    $timeout = 5;
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
    $data = curl_exec($ch);
    curl_close($ch);
    return $data;
}

$returned_content = get_data('http://freedomainapi.com/?key=XXXXXXX&domain=' . $domain);

echo $returned_content;

?>

When called as such: /domchek.php?domname=google.com

The JSON output is:

{"status":"success","domain":"google.com","available":true}

The JQuery im using to call the script is as follows:

$.get("domchek.php?domname=google.com", {data: "available"}, function(json) {
    $("html").html(json);
});

I just want to return the availability not the entire JSON output. I have tried json.availability and a number of other things but can't figure it out. Also if there is a better method for this than .get() please suggest it.

UPDATE:

$.getJSON("domchek.php?domname=google.com", function(json) {
  $("html").html(json.status);
});

The above works as does returning json.domain but trying to return json.available - which I require returns nothing..

  • 写回答

1条回答 默认 最新

  • weixin_33737774 2013-11-18 02:40
    关注

    Change this line:

    $("html").html(json);
    

    to:

    $("html").html(json.status);
    

    UPDATE: to force the GET request data type to JSON, change to:

    $.get("domchek.php?domname=google.com", {data: "available"}, function(json) {
        $("html").html(json);
    }, 'json');
    
    评论

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