关闭不与Ajax一起使用

Question

I'm using a looped ajax call with a closure but the value of the variable isn't being retained. It takes the value from the last iteration.

for(int i = 0; i < data.length; i++) {
    createElement(data[i], otherdata[i]);
}

function createElement(d,od){
    d.success = function(r) { console.log(od) };
    $.ajax(d);
}

lets say otherdata= [1,2,3]. the log will show '3' three times any ideas why this is happening

Answer 1

There are no types in javascript, use var instead of int in your loop, and fix the syntax errors.

for(var i=0; i<data.length;i++){
    createElement(data[i],otherdata[i]);
}