jQuery Ajax异常捕获器

Question

I'm stuck with a simple exception that I can't catch:

//myScript.js.coffee
try
  $.ajax
    async: false
    type: "GET"
    url: index_url
    success: ->
      //Do something
    error: ->
      //Do something else
    fail: ->
      //Do something else
catch e
  console.log e

When I try to call this Ajax with a bad url, there is an error and nothing caught it. Does any one have an idea ?

Basically I would like to test the url before calling this ajax request.

Edit: I know that putting a try/catch with an asynchronous function is useless but it's to show that I tried different ways to catch those exceptions but nothing works.

Answer 1

Your sintax is wrong:

try {
    $.ajax {
        async: false,
        type: "GET",
        url: index_url,
        success: function(data) {
            alert ("post is success");
        },
        error: function(request,error) { 
            alert(request.responseText);
            alert(error);
        }
    }
} catch (e) {
    console.log(e);
}

But as suggested, you can use the ajax response to do what you want depending the result...