判断数组money相同数据就合并，求解

Question

let arry = [{
        name: '张三', age: 18,
        list: [{ num: 21, list1: [{ money: 1, money2: '', money3: 4 }] },
        { num: 21, list1: [{ money: 2, money2: '5', money3: '' }] },
        { num: 21, list1: [{ money: 2, money2: '', money3: '2' }] }]
    }, {
        name: '里斯',
        age: 19,
        list: [{ num: 22, list1: [{ money: 1, money2: '', money3: '' }] },
        { num: 22, list1: [{ money: 3, money2: '8', money3: 10 }] }
        ]
    },
{
        name: '小名',
        age: 21,
        list: [{ num: 23, list1: [{ money: 1, money2: '', money3: '' }] },
        { num: 23, list1: [{ money: 3, money2: '8', money3: 10 }] },
{ num: 23, list1: [{ money: 1, money2: '', money3: '' }] }
        ]
    }
    ]
    let allData = []
    for (let a in arry) {
        let name = arry[a].name
        var mList = arry[a].list
        var List = [];
        for (let m in mList) {
            if (List.length == 0) {
                List.push(mList[m]);
            }
            else {
                var isBool = false;
                for (let s in mList[m].list1) {
                    for (let c in List) {
                        for (let b in List[c].list1) {
                            if (mList[m].list1[s].money == List[c].list1[b].money) {
                                for (let key of Object.keys(List[c].list1[b])) {
                                    List[c].list1[b][key] = mList[m].list1[s][key]
                                }
                                isBool = false;
                                break;
                            } else {
                                isBool = true;
                            }
                        }
                    }  
                }
                if (isBool) {
                    List.push(mList[m]);
 console.log(mList[m],m);
                }
            }
        }

        arry[a].list = List;
    }
    console.log(arry);

打印结果

[
   {
    "name":"张三",
     "age":18,
      "list":[{"num":21,
                  "list1":[{"money":1,"money2":"","money3":4}]},
                                { num: 21,
                                    list1: [{ money: 2, money2: '2', money3: '2' }] }]},
  {
    "name":"里斯",
    "age":19,
    "list":[{"num":22,
              "list1":[{"money":1,"money2":"","money3":""}]},
            {"num":22,
              "list1":[{"money":3,"money2":"8","money3":10}]}]},
{
"name":"小名",
"age":21,
list: [{ num: 23, list1: [{ money: 1, money2: '', money3: '' }] },
        { num: 23, list1: [{ money: 3, money2: '8', money3: 10 }] },
        { num: 23, list1: [{ money: 1, money2: '', money3: '' }] } ]
}]

数据第一条相同的合并了，但第三条切换了一下money相同的位置数据就不对了 既合并了 又还多了一条 求解

Answer 1

https://www.cnblogs.com/lingdu87/p/9592320.html