如何去掉日期中填充的0
f:今天8月1号,生成的文件名字就是8.1()
我的命令:
@echo off
set month=%date:~5,2%
set day=%date:~8,2%
echo %month%|findstr "^0+\d+$" >nul
if %errorlevel% equ 1 set month=%month:~1,1%
md %month%
echo 创建了名字为:%month%的文件夹
pause
问题:
如何筛选0开头的月份和日期
我的命令:
@echo off
set month=%date:~5,2%
set day=%date:~8,2%
echo %month%|findstr "^0+\d+$" >nul
if %errorlevel% equ 1 set month=%month:~1,1%
md %month%
echo 创建了名字为:%month%的文件夹
pause
问题:
如何筛选0开头的月份和日期
set str_time_first_bit="%time:~0,1%"
if %str_time_first_bit%==" " (
set str_date_time=%date:~0,4%%date:~5,2%%date:~8,2%_0%time:~1,1%%time:~3,2%%time:~6,2%
)else (
set str_date_time=%date:~0,4%%date:~5,2%%date:~8,2%_%time:~0,2%%time:~3,2%%time:~6,2%
)
md %str_date_time%_backups