halcon阈值分割以及区域转换

Question

求助，截取图片左边的那张，阈值分割得到区域，并将得到的区域分别转换成凸区域，最小外接圆区域，平行于坐标轴的最大内接矩形，不平行于坐标轴的最小外接矩形。 求组halcondai'ma

Answer 1

read_image (Image, 'C:/Users/Desktop/1603762504_281806.jpg')

gen_rectangle1 (ROI_0, 387.063, 293.962, 723.347, 790.507)

reduce_domain(Image, ROI_0, ImageReduced)

threshold (ImageReduced, Regions, 0, 116)
*凸区域RegionTrans
shape_trans(Regions, RegionTrans, 'convex')
*最小外接圆区域RegionTrans1
shape_trans(Regions, RegionTrans1, 'outer_circle')

*平行于坐标轴的最大内接矩形RegionTrans2
shape_trans(Regions, RegionTrans2, 'inner_rectangle1')

*不平行于坐标轴的最小外接矩形Rectangle
smallest_rectangle2(Regions, Row, Column, Phi, Length1, Length2)
gen_rectangle2(Rectangle, Row, Column, Phi, Length1, Length2)