输出integer创建的对象,为啥不是地址值

Question

输出integer创建的对象,为啥不是地址值

Answer 1

因为Integer类里重写了toString方法。点进去看一下源码就明白了。

public class  DemoCSDN {
    public static   void main(String[] args) {
        A a = new A();
        a.setName("zhangsan");
        a.setAdress("nanjing");
        System.out.println(a);//如果重写了toString，控制台打印：A{name='zhangsan', adress='nanjing'}，否则打印：com.company.A@610455d6

        //Integer类里重写了toString方法。如下：
        /*
         public static String toString(int i, int radix) {
        if (radix < Character.MIN_RADIX || radix > Character.MAX_RADIX)
            radix = 10;
         Use the faster version
        if (radix == 10) {
            return toString(i);
        }
        char buf[] = new char[33];
        boolean negative = (i < 0);
        int charPos = 32;
        if (!negative) {
            i = -i;
        }
        while (i <= -radix) {
            buf[charPos--] = digits[-(i % radix)];
            i = i / radix;
        }
        buf[charPos] = digits[-i];
        if (negative) {
            buf[--charPos] = '-';
        }
        return new String(buf, charPos, (33 - charPos));
    }
        * */
    }

}
class A{
String name ;
String adress;
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public String getAdress() {
        return adress;
    }
    public void setAdress(String adress) {
        this.adress = adress;
    }

}