除去数组中重复的部分，最后那一步有问题，我发现不了

Question

public static int[] EliminateDuplication(int[] list) {
		
		boolean tu = true;
		int duplicationNumber = 0;
		for (int i = 0; i < list.length; i++) {
			tu = true;
			for (int j = i + 1; j < list.length && tu; j++) {
				if (list[i] == list[j]) {
					duplicationNumber++;
					tu = false;
					
				}
			}
		}
		
		int[] dupIndex = new int[duplicationNumber ];
		int a = 0; 
		for (int i = 0; i < list.length; i++) {
			tu = true;
			for (int j = i + 1; j < list.length && tu; j++) {
				if ((list[i] == list[j])) {
					dupIndex[a] = j;
					a++;
					tu = false;
				}
			}
		}
		
		for (int i = 0; i < dupIndex.length; i++)
			System.out.print(dupIndex[i] + " ");
		
		int[] listx = new int[list.length - duplicationNumber];
		int tt = 0;
		int j = 0;
		for(int i = 0; i < listx.length; i++) {
			tu = true;
			while(j < list.length) {
				if(tu) {   
   				   for (int b = 0; b < dupIndex.length; b++) {
     	    			if (j == dupIndex[b]) {
     	    				tt++;
     		    		}	
	    		   }
   				   
   				   if (tt == 0) {
   					   listx[i] = list[j];
   				       tu = false;
   				   }
				}
				j++;
		    }
		}
		
		return listx;
	}

Answer 1

// 最后的for循环
for (int i = 0; i < listx.length; i++) {
    tu = true;
    while (tu) {
        for (int b = 0; b < dupIndex.length; b++) {
            if (j == dupIndex[b]) {
                tt++;
                break;
            }
        }

        if (tt == 0) {
            listx[i] = list[j];
            tu = false;
        } else {
            tt = 0;
        }
        j++;
    }
}