qingfenglina11 2013-07-01 13:34 采纳率: 0%
浏览 2370

web开发,jsp界面设计出错

<%@ page language="java" pageEncoding="gbk"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">

    <title>My JSP 'error.jsp' starting page</title>

    <meta http-equiv="pragma" content="no-cache">
    <meta http-equiv="cache-control" content="no-cache">
    <meta http-equiv="expires" content="0">    
    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
    <meta http-equiv="description" content="This is my page">
    <!--
    <link rel="stylesheet" type="text/css" href="styles.css">
    -->

  </head>

  <body>
     <font color="#rrddb">操作失败!</font> <br>
  </body>
</html>

显示<%

String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

模块出现错误,不知道怎么解决,请求高手。大家帮帮忙啊,在此谢谢了。
如果删除<%

String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>就会显示<base href="<%=basePath%>">错误。
  • 写回答

3条回答

  • MavisVermilion 2013-07-01 17:25
    关注
    <%
    String path = request.getContextPath();
    String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
    %>
    

    这几行擦掉就行~

    评论

报告相同问题?