for_2012 2013-01-29 09:00 采纳率: 0%
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怎么限制除了点和下划线的特殊字符

怎么限制UITextField 中的特殊字符?只保留点和下划线。我用了下面的代码,但是没有反应:

#define ACCEPTABLE_CHARECTERS @" ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789_."

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
         NSCharacterSet *acceptedInput = [NSCharacterSet characterSetWithCharactersInString:ACCEPTABLE_CHARECTERS];
        if (![[string componentsSeparatedByCharactersInSet:acceptedInput] count] > 1){
            NSLog(@"not allowed");
            return NO;
        }
        else{
            return YES;
        }
}
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1条回答

  • Matt 2013-01-30 16:45
    关注

    我想了好半天,不知道怎么回答好...因为方法太多了...
    方法一: 使用scaner(如果你坚持要自定义accetpable的字符)

    NSString *yourString = @"tBe47s_-#h54df";
    
    NSMutableString *resultString = [NSMutableString stringWithCapacity:yourString.length];
    
    NSScanner *scanner = [NSScanner scannerWithString:yourString];
    NSCharacterSet *charSet = [NSCharacterSet characterSetWithCharactersInString:@"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789_."];
    
    while ([scanner isAtEnd] == NO)
    {
        NSString *buffer;
        if ([scanner scanCharactersFromSet:charSet intoString:&buffer])
            [resultString appendString:buffer];
        else
            [scanner setScanLocation:([scanner scanLocation] + 1)];
    }
    
    NSLog(@"result: %@", resultString);
    

    方法二:正则表达式(iOS4.0以后适用,4之前要用第三方库)

    NSString *yourString = @"tBe%#&4.7s_-#h5S4df";
    NSError *error = NULL;
    NSRegularExpression *regex = [NSRegularExpression
                                  regularExpressionWithPattern:@"([^A-Za-z0-9_.])"
                                  options:0
                                  error:&error];
    
    NSString *resString = [regex stringByReplacingMatchesInString:yourString options:0 range:NSMakeRange(0, yourString.length) withTemplate:@""];
    NSLog(@"result: %@", resString);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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