这个程序怎么老是有警告,不能运行!!
#include
#include
int i,j;
int main()
{
void sort(char *name[],int n);
void output(char *name[],int n);
char *name[]={"Follow me","BASIC","Great wall","FORTRAN","Computer design"};
int n=5;
sort(name,n);
output(name,n);
return 0;
}
void sort(char *name[],int n)
{
char *temp;
int k;
for(i=0;i
{
k=i;
for(j=i+1;j
if(strcpy(name[k],name[j])>0)
k=j;
if(k!=i)
{
temp=name[i];
name[i]=name[k];
name[k]=temp;
}
}
}
void output(char *name[],int n)
{
for(i=0;i<n;i++)
printf("%s\n",name[i]);
}
qian言wan语
2014/08/29 12:59- c
- 点赞
- 收藏
- 回答
3个回复
