python 无法停止递归 求解啊

Question

def dfs1(x,y):
show[x][y]='.'
for i in f:
for j in f:
nx=x+i
ny=y+j
if(nx>=0 and ny>=0 and nx dfs1(nx,ny)
if(nx>=0 and ny>=0 and nx<10 and ny<10 and ans[nx][ny]!=0 and mine[nx][ny]!=1 and(i!=0 or j!=0)and(i==0 or j==0)):
show[nx][ny]=ans[nx][ny]
return 0
return 0

Answer 1

python很大程度依赖缩进，这种代码没法看