#include
#include
typedef struct node{
int num;
char ch;
}NODE;
int main(void){
int n,i;
NODE F;
printf("input n:");
scanf("%d",&n);
F=(NODE)malloc(n*sizeof(NODE*));
printf("input num and ch:");
for(i=0;i
F[i]=(NODE*)malloc(sizeof(NODE));
scanf("%c",&F[i]->num);//fflash(stdin);
scanf("%d",&F[i]->ch);//fflash(stdin);
}printf("输入结束\n");
for(i=0;i
printf("%d",F[i]->num);
printf("%c",F[i]->ch);
}printf("输结束\n");
for(i=0;i<n;++i)
free(F[i]);
free(F);
}就是想使F成为指向结构体的指针数组,然后通过F对个元素赋值,并输出
输出结果:
input n:3
input num and ch:
1 a 2 b 3 c
输入结束
-842150646.-842150624?842150559.输结束
Press any key to continue
输出结果是怎么回事呢?