yue1liang1chuan 2013-03-05 02:39 采纳率: 0%
浏览 2459
已采纳

AFNetworking valueForKeyPath通配符

我正在从下面的JSON文件中获取tvrage_name:

{
    data: {
           Band of Brothers: {
                              air_by_date: 0,
                              cache: {
                                      banner: 1,
                                      poster: 1
                                      },
                              language: "en",
                              network: "HBO",
                              next_ep_airdate: "",
                              paused: 0,
                              quality: "Any",
                              status: "Ended",
                              tvdbid: 74205,
                              tvrage_id: 2708,
                              tvrage_name: "Band of Brothers"
                              },
           Breaking Bad: {
                              air_by_date: 0,
                              cache: {
                              banner: 1,
                              poster: 1
                              },
                              language: "en",
                              network: "AMC",
                              next_ep_airdate: "2013-07-14",
                              paused: 0,
                              quality: "HD",
                              status: "Continuing",
                              tvdbid: 81189,
                              tvrage_id: 18164,
                              tvrage_name: "Breaking Bad"
                              },
          },
          message: "",
          result: "success"
}

能不能在valueForKeyPath中有一个通配符?这样valueForKeyPath可以成为:data.*.tvrage_name(其中*就是通配符)

  • 写回答

1条回答 默认 最新

  • Mr_me 2013-03-05 03:40
    关注

    你需要去遍历值/key,像这样:

    ...
    NSDictionary *data = [JSON valueForKey:@"data"];
    for (NSString *movie in data) {
        NSLog(@"tvrage_name: %@", [[data valueForKey:movie] valueForKey:@"tvrage_name"]);
    }
    ...
    

    为了保险起见我会做额外的检查e.g. [JSON isKindOfClass:[NSDictionary class]]

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?