如果 pData[Count]={4000,1700,1600,1400,1345,1200,1050,870,452,450,297,120,110,104,98,.....}
int* OptimizeData(int *pData,int Count,int Length); //Count 总个数,Length固定长度(6000)
{
int *a=new int[Count];
将pData[]数组中任意个数相加最接近Length(6000)的一组一组输出到a[];
..................
return a;
}
结果a[Count]={4000,1700,297,1600,1400,1345,1200,452,1050,870,450,120,110,104,98.....}
{(4000,1700,297,)(1600,1400,1345,1200,450,)(1050,870,450,120,110,104,98..)...}