开发中需要这样的功能，将String str = "0f8adffb11dc" 转换为byte[] byteText = { 0x0f, 0x8a, 0xdf, 0xfb,0x11, 0xdc};请问如何实现，谢谢！
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- danielinbiti 2015-05-18 14:49已采纳
public class Test { public static byte uniteBytes(byte src0, byte src1) { byte _b0 = Byte.decode("0x" + new String(new byte[]{src0})).byteValue(); _b0 = (byte)(_b0 << 4); byte _b1 = Byte.decode("0x" + new String(new byte[]{src1})).byteValue(); byte ret = (byte)(_b0 ^ _b1); return ret; } public static byte[] HexString2Bytes(String src){ byte[] ret = new byte[src.length()/2]; byte[] tmp = src.getBytes(); for(int i=0; i<src.length()/2; i++){ ret[i] = uniteBytes(tmp[i*2], tmp[i*2+1]); } return ret; } public static void main(String[] args) { byte[] byteText = { 0x0f, (byte) 0x8a, (byte) 0xdf, (byte) 0xfb,0x11, (byte) 0xdc}; byte[] ret = Test.HexString2Bytes("0f8adffb11dc"); } }已采纳该答案赞 踩 打赏 评论分享 - threenewbee 2015-05-18 15:33
String str = "0f8adffb11dc";
byte[] result = new byte[str.length() / 2];
for (int i = 0; i < str.length(); i += 2)
{
result[i / 2] = Byte.parse(str.subString(i, 2), 16);
}1 踩 打赏 评论分享 - oyljerry 2015-05-18 14:47
两位字符串一组截取，然后转换成十六进制数据。
赞 踩 打赏 评论分享 - 三少爷的大宝剑 2015-05-19 02:51
string str = "0f8adffb11dc";
byte[] resultList = new byte[str.Length / 2];
for (int i = 0; i < str.Length / 2; i++)
{
resultList[i] = Convert.ToByte(str.Substring(i * 2, 2), 16);
}赞 踩 打赏 评论分享