ajax怎样获取返回的特定值

Question

ajax代码
//声明XMLHttpRequest对象
var xmlrequest;

//初始化XMLHttpRequest
function createXMLHttpRequest(){
if(window.XMLHttpRequest){
xmlrequest = new XMLHttpRequest();
}else if(window.ActiveXObject){
try{
xmlrequest = new ActiveXObject("Msxml2.XMLHTTP");
}catch(e){
try{
xmlrequest = new ActiveXObject("Microsoft.XMLHTTP");
}catch(e){

        }
    }
}

}

//定义回调函数
function processResponse(){
//响应完成
if(xmlrequest.readyState == 4){
//响应正常
if(xmlrequest.status == 200){
var head = xmlrequest.responseText;
alert(head);
// location.href = head;

    }
}

}

//事件处理函数
function change(){
//初始化XMLHttpRequest对象
createXMLHttpRequest();

//设置请求的URI
var uri = "servlet/LoginServlet";

//打开与服务器响应地址的连接
xmlrequest.open("POST", uri, true);

//设置请求头
xmlrequest.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
//设置处理响应的回调函数
xmlrequest.onreadystatechange = processResponse;
var account = document.form.account.value;
var password = document.form.password.value;
//发送请求
xmlrequest.send("account=" + account + "&password=" + password);

}

servlet代码：
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
System.out.println("post被触发了");
request.setCharacterEncoding("UTF-8");
response.setContentType("text/html;charset=UTF-8");

    String account = request.getParameter("account");
    String password = request.getParameter("password");

// if (account == "admin" & password == "admin"){
HttpSession session=request.getSession();
session.setAttribute("client","返回的用户名");
PrintWriter out = response.getWriter();

  out.print("index.jsp");
  out.print("返回了吗");


        我要怎样做才能获取上面那两个our.print的值呢，是分别获取，不是组成一个字符串

Answer 1

那你用字符串分隔下，客户端js split下得到内容

  out.print("index.jsp|");///|分隔
  out.print("返回了吗");

 var head = xmlrequest.responseText;
var arr=head.split('|');//拆分
alert(arr[0])
alert(arr[1])

有用记得采纳。。