android开发使用UDP进行通信中通过DatagramSocket创建对象抛出异常

Question

我是刚来的，没有c币，求好心人帮忙解答，谢谢谢谢！！！！
package com.example.practice;

import java.net.DatagramSocket;
import java.net.SocketException;

import android.os.Bundle;
import android.app.Activity;

public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    new kaishi().start();
}

class kaishi extends Thread{

    @Override
    public void run() {
        // TODO Auto-generated method stub
        System.out.println("01");
        try {
            System.out.println("03");
            DatagramSocket socket =new DatagramSocket(50000);    //异常,原因 套接字不能被打开
            System.out.println("05");
        } catch (SocketException e) {
            System.out.println("02");
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        System.out.println("04");
    }
    }

}

··················································································
以上是一个android软件一个代码，目的是用UDP协议进行手机之间的通信，代码内容仅仅就是创建一个DatagramSocket对象。问题是：每次程序进行到创建DatagramSocket对象的时候都会抛出异常，用真机测试输出结果是：01 03 02 04。这是在Android的工程中写的，在java工程中就可以成功创建，语法是按照Java的API写的，但每次都抛出异常，网上说是因为端口号被占用才抛出异常，换了好几个端口号还是会抛出异常。求可以成功创建DatagramSocket对象的方法.

Answer 1

 protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    System.out.println("01");
    try {
        System.out.println("03");
                new Thread(){
            public void run(){
                DatagramSocket socket =new DatagramSocket(50000);    //异常,原因 套接字不能被打开
            }
        }.start();
        System.out.println("05");
    } catch (SocketException e) {
        System.out.println("02");
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    System.out.println("04");
}