SQL 表A(id,no,name)、表C(no)怎么判断每个人缺少的no并且把缺少的新增进表A

Question

表A数据
(1,'A','张三')
(1,'B','张三')
(2,'A','李四')
(3,'B','王五')

表C数据
(A)
(B)
(C)

怎么判断每个人缺少的no并且把缺少的新增进表A ？？？
如张三缺少C，则新增(1,'C','张三')；
李四缺少B、C，则新增(2,'B','李四')(2,'C','李四')
以此类推、、、

Answer 1

 create table ma(
   id int,
   fe varchar(20),
   vname varchar(20)
);
insert into ma values(1,'A','张三');
insert into ma values(1,'B','张三');
insert into ma values(2,'A','李四');
insert into ma values(3,'B','王五');
create table mb(
  fe varchar(20)
);

insert into mb values('A');
insert into mb values('B');
insert into mb values('C');
insert into ma(id,fe,vname) values(
SELECT id,vname,fe FROM (
select c.*,c.vname + ','+c.fe as kid from (
select * from 
(
select distinct id,vname from ma
) a,
(select fe from mb)
b 
) c 
) D 
where kid not in(SELECT VNAME+','+FE FROM ma)
)