关于单片机的数码管扫描

Question

为什么下面的程序在现实的不是扫描而是有点乱
#include
#define uint unsigned int
#define uchar unsigned char

sbit LE1=P2^0; //位选573锁存器使能
sbit LE2=P2^1; //段选573锁存器使能
void delay (int time)
{
uint i,j;
for (i=0;i<time;i++)
for (j=0;j<50;j++);
}
uchar code dis[16]={0x3F,0x06,0x5B,0x4F,0x66,0x6D,0x7D,0x07,

0x7F,0x6F,0x77,0x7C,0x39,0x5E,0x79,0x71};

uchar code step[8]={0x7f,0xbf,0xcf,0xdf,0xf7,0xfb,0xfc,0xfd};
void main ()
{
while (1)
{
uint i;
for (i=0;i<8;i++)
{
P1=step[i];
LE1=1;
LE1=0;
P1=dis[i];
LE2=1;
LE2=0;
delay(8000);
}
}
}

Answer 1

代码这么贴，太乱了。