# 想要实现的是小写金额转换成大写金额

``````  <TR>
<TD align="left" class="tdp">规格：</TD>
<TD align="left" class="tdp" width="15%"><s:property value="ruKu.guiGe"/></TD>
<TD align="left" class="tdp" >实际重量：</TD>
<TD align="left" class="tdp" width="15%"><s:property value="ruKu.shiJiZongLiang"/></TD>
<TD align="left" class="tdp">大写金额：</TD>
<TD align="left" class="tdp" width="15%"><s:property value="  "/></TD>
</TR>
``````
``````
function atoc(numberValue){
var numberValue=new String(Math.round(numberValue*100)); // 数字金额
var chineseValue=""; // 转换后的汉字金额
var String1 = "零壹贰叁肆伍陆柒捌玖"; // 汉字数字
var String2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"; // 对应单位
var len=numberValue.length; // numberValue 的字符串长度
var Ch1; // 数字的汉语读法
var Ch2; // 数字位的汉字读法
var nZero=0; // 用来计算连续的零值的个数
var String3; // 指定位置的数值
if(len>15){
return "";
}
if (numberValue==0){
chineseValue = "零元整";
return chineseValue;
}
String2 = String2.substr(String2.length-len, len); // 取出对应位数的STRING2的值
for(var i=0; i<len; i++){
String3 = parseInt(numberValue.substr(i, 1),10); // 取出需转换的某一位的值
if ( i != (len - 3) && i != (len - 7) && i != (len - 11) && i !=(len - 15) ){
if ( String3 == 0 ){
Ch1 = "";
Ch2 = "";
nZero = nZero + 1;
}
else if ( String3 != 0 && nZero != 0 ){
Ch1 = "零" + String1.substr(String3, 1);
Ch2 = String2.substr(i, 1);
nZero = 0;
}
else{
Ch1 = String1.substr(String3, 1);
Ch2 = String2.substr(i, 1);
nZero = 0;
}
}
else{ // 该位是万亿，亿，万，元位等关键位
if( String3 != 0 && nZero != 0 ){
Ch1 = "零" + String1.substr(String3, 1);
Ch2 = String2.substr(i, 1);
nZero = 0;
}
else if ( String3 != 0 && nZero == 0 ){
Ch1 = String1.substr(String3, 1);
Ch2 = String2.substr(i, 1);
nZero = 0;
}
else if( String3 == 0 && nZero >= 3 ){
Ch1 = "";
Ch2 = "";
nZero = nZero + 1;
}
else{
Ch1 = "";
Ch2 = String2.substr(i, 1);
nZero = nZero + 1;
}
if( i == (len - 11) || i == (len - 3)){ // 如果该位是亿位或元位，则必须写上
Ch2 = String2.substr(i, 1);
}
}
chineseValue = chineseValue + Ch1 + Ch2;
}
if ( String3 == 0 ){ // 最后一位（分）为0时，加上“整”
chineseValue = chineseValue + "整";
}
return chineseValue;
}
``````

2015/09/01 04:02
• java
• 小写变大写
• javascript
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