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sinat_31173723 文本
4 年多之前 回复

C语言文件简单加密与解密

c语言文件加密，加密出现问题，解密不了
c语言 文件加密问题

C语言关于加密解密过程？

C语言实现RSA解密时的一个问题

Problem Description The Sarcophagus itself is locked by a secret numerical code. When somebody wants to open it, he must know the code and set it exactly on the top of the Sarcophagus. A very intricate mechanism then opens the cover. If an incorrect code is entered, the tickets inside would catch fire immediately and they would have been lost forever. The code (consisting of up to 100 integers) was hidden in the Alexandrian Library but unfortunately, as you probably know, the library burned down completely. But an almost unknown archaeologist has obtained a copy of the code something during the 18th century. He was afraid that the code could get to the ``wrong people'' so he has encoded the numbers in a very special way. He took a random complex number B that was greater (in absolute value) than any of the encoded numbers. Then he counted the numbers as the digits of the system with basis B. That means the sequence of numbers an, an-1, ..., a1, a0 was encoded as the number X = a0 + a1B + a2B2 + ...+ anBn. Your goal is to decrypt the secret code, i.e. to express a given number X in the number system to the base B. In other words, given the numbers X and Byou are to determine the ``digit'' a0 through an. Input The input consists of T test cases. The number of them (T) is given on the first line of the input file. Each test case consists of one single line containing four integer numbers Xr, Xi, Br, Bi (|Xr|,|Xi| <= 1000000, |Br|,|Bi| <= 16). These numbers indicate the real and complex components of numbers X and B, i.e. X = Xr + i.Xi, B = Br + i.Bi. B is the basis of the system (|B| > 1), X is the number you have to express. Output Your program must output a single line for each test case. The line should contain the ``digits'' an, an-1, ..., a1, a0, separated by commas. The following conditions must be satisfied: for all i in {0, 1, 2, ...n}: 0 <= ai < |B| X = a0 + a1B + a2B2 + ...+ anBn if n > 0 then an <> 0 n <= 100 If there are no numbers meeting these criteria, output the sentence "The code cannot be decrypted.". If there are more possibilities, print any of them. Sample Input 4 -935 2475 -11 -15 1 0 -3 -2 93 16 3 2 191 -192 11 -12 Sample Output 8,11,18 1 The code cannot be decrypted. 16,15
DES加解密，Java和C里面的填充内容的问题
DES加解密的时候遇到一个问题：C语言中不足八位填充的是‘\0’，我在Java中也是填的这个，但是加密后传给C程序解密失败，两边加密出来的内容不一致！！求教，怎么解决啊！！！C币用完了 求好心人

Problem Description Xiaoming has just come up with a new way for encryption, by calculating the key from a publicly viewable number in the following way: Let the public key N = AB, where 1 <= A, B <= 1000000, and a0, a1, a2, …, ak-1 be the factors of N, then the private key M is calculated by summing the cube of number of factors of all ais. For example, if A is 2 and B is 3, then N = AB = 8, a0 = 1, a1 = 2, a2 = 4, a3 = 8, so the value of M is 1 + 8 + 27 + 64 = 100. However, contrary to what Xiaoming believes, this encryption scheme is extremely vulnerable. Can you write a program to prove it? Input There are multiple test cases in the input file. Each test case starts with two integers A, and B. (1 <= A, B <= 1000000). Input ends with End-of-File. Note: There are about 50000 test cases in the input file. Please optimize your algorithm to ensure that it can finish within the given time limit. Output For each test case, output the value of M (mod 10007) in the format as indicated in the sample output. Sample Input 2 2 1 1 4 7 Sample Output Case 1: 36 Case 2: 1 Case 3: 4393

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C使用openssl RSA base64对数据进行加密解密出错

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