初学c语言图形化编程问个很简单的问题

Question

写37行代码就为了画个围棋棋盘值不值？有更简洁的算法吗？

 #include<graphics.h>
#include<conio.h>
#define LEN 30  // 每格间的距离
int main()
{
    int x, y;
    initgraph(660, 660);
    // 背景上色
    setcolor(BROWN);
    for(y = 0; y < 660; y++)
        line(0, y, 660, y);
    // 绘制边框
    setcolor(BLACK);
    line(35, 35, 45+540, 35);
    line(35, 45+540, 45+540, 45+540);
    line(35, 35, 35, 45+540);
    line(45+540, 35, 45+540, 45+540);
    for(y = 40; y<=40+LEN*18; y+=LEN)
        line(40, y, 40+LEN*18, y);
    for(x = 40; x<=40+LEN*18; x+=LEN)
        line(x, 40, x, 40+LEN*18);
    // 绘制黑点
    setfillcolor(BLACK);
    fillcircle(40+3*LEN,  40+3*LEN, 2);
    fillcircle(40+9*LEN,  40+3*LEN, 2);
    fillcircle(40+15*LEN, 40+3*LEN, 2);
    fillcircle(40+3*LEN,  40+9*LEN, 2);
    fillcircle(40+9*LEN,  40+9*LEN, 2);
    fillcircle(40+15*LEN, 40+9*LEN, 2);
    fillcircle(40+3*LEN,  40+15*LEN,2);
    fillcircle(40+9*LEN,  40+15*LEN,2);
    fillcircle(40+15*LEN, 40+15*LEN,2);
    getch();
    closegraph();
    return 0;

Answer 1

     fillcircle(40+3*LEN,  40+3*LEN, 2);
    fillcircle(40+9*LEN,  40+3*LEN, 2);
    fillcircle(40+15*LEN, 40+3*LEN, 2);
    fillcircle(40+3*LEN,  40+9*LEN, 2);
    fillcircle(40+9*LEN,  40+9*LEN, 2);
    fillcircle(40+15*LEN, 40+9*LEN, 2);
    fillcircle(40+3*LEN,  40+15*LEN,2);
    fillcircle(40+9*LEN,  40+15*LEN,2);
    fillcircle(40+15*LEN, 40+15*LEN,2);

可以简化为

for (int i = 1; i <= 3; i++)
    for (int j = 1; j <= 3; j++)
        {
            fillcircle(40+3*i*LEN,  40+3*j*LEN, 2);
        }