tuzikyy 2015-11-20 12:59 采纳率: 50%
浏览 1402
已采纳

c#入门级问题求大手子解决

Random r = new Random();
int d1 = r.Next( 1, 7 );
int d2 = r.Next( 1, 7 );
int sum = d1 + d2;
Console.WriteLine("Player rolled {0} + {1} = {2}",d1, d2, sum);
switch (sum)
{
case 11:
Console.WriteLine("player win");
break;
case 7:
Console.WriteLine("player win");
break;
case 2:
Console.WriteLine("player lose");
break;
case 3:
Console.WriteLine("player lose");
break;
case 12:
Console.WriteLine("player lose");
break;
default :
Console.WriteLine("Point is {0}", sum);
break;
}
if (sum != 11||sum != 12||sum !=7||sum != 2||sum !=3)
{
int q1 = r.Next(1, 7);
int q2 = r.Next(1, 7);
int o = q1 + q2;
Console.WriteLine("Player rolled {0} + {1} = {2}", q1, q2, o);
if (o == sum)
{
Console.WriteLine("player win");
}
while (o != sum)
{
int y1 = r.Next(1, 7);
int y2 = r.Next(1, 7);
int s = y1 + y2;
Console.WriteLine("Player rolled {0} + {1} = {2}", y1, y2, s);
o = s;
if (s == sum)
{
Console.WriteLine("player win");
break;
}
else if (s == 7)
{
Console.WriteLine("player lose");
break;
}
}
}
Random r = new Random();
int d1 = r.Next( 1, 7 );
int d2 = r.Next( 1, 7 );
int sum = d1 + d2;
Console.WriteLine("Player rolled {0} + {1} = {2}",d1, d2, sum);
switch (sum)
{
case 11:
Console.WriteLine("player win");
break;
case 7:
Console.WriteLine("player win");
break;
case 2:
Console.WriteLine("player lose");
break;
case 3:
Console.WriteLine("player lose");
break;
case 12:
Console.WriteLine("player lose");
break;
default :
Console.WriteLine("Point is {0}", sum);
break;
}
if (sum != 11||sum != 12||sum !=7||sum != 2||sum !=3)
{
int q1 = r.Next(1, 7);
int q2 = r.Next(1, 7);
int o = q1 + q2;
Console.WriteLine("Player rolled {0} + {1} = {2}", q1, q2, o);
if (o == sum)
{
Console.WriteLine("player win");
}
while (o != sum)
{
int y1 = r.Next(1, 7);
int y2 = r.Next(1, 7);
int s = y1 + y2;
Console.WriteLine("Player rolled {0} + {1} = {2}", y1, y2, s);
o = s;
if (s == sum)
{
Console.WriteLine("player win");
break;
}
else if (s == 7)
{
Console.WriteLine("player lose");
break;
}
}
}
Random r = new Random();
int d1 = r.Next( 1, 7 );
int d2 = r.Next( 1, 7 );
int sum = d1 + d2;
Console.WriteLine("Player rolled {0} + {1} = {2}",d1, d2, sum);
switch (sum)
{
case 11:
Console.WriteLine("player win");
break;
case 7:
Console.WriteLine("player win");
break;
case 2:
Console.WriteLine("player lose");
break;
case 3:
Console.WriteLine("player lose");
break;
case 12:
Console.WriteLine("player lose");
break;
default :
Console.WriteLine("Point is {0}", sum);
break;
}
if (sum != 11||sum != 12||sum !=7||sum != 2||sum !=3)
{
int q1 = r.Next(1, 7);
int q2 = r.Next(1, 7);
int o = q1 + q2;
Console.WriteLine("Player rolled {0} + {1} = {2}", q1, q2, o);
if (o == sum)
{
Console.WriteLine("player win");
}
while (o != sum)
{
int y1 = r.Next(1, 7);
int y2 = r.Next(1, 7);
int s = y1 + y2;
Console.WriteLine("Player rolled {0} + {1} = {2}", y1, y2, s);
o = s;
if (s == sum)
{
Console.WriteLine("player win");
break;
}
else if (s == 7)
{
Console.WriteLine("player lose");
break;
}
}
}
一个扔骰子问题,先扔两次,和为7或11,玩家赢,为2,3或12为玩家输,若为其他数,则这个数为“点数”,继续扔,一直扔到和为点数,玩家赢。但若和为7时,玩家输。
问题是if (sum != 11||sum != 12||sum !=7||sum != 2||sum !=3)没有起作用,不管第一次扔赢还是输,总会扔第二次。

  • 写回答

1条回答 默认 最新

  • Revolution_lxx 2015-11-20 13:07
    关注

    if (sum != 11||sum != 12||sum !=7||sum != 2||sum !=3)

    =====================>>>>>>>>>>>>

    if (sum != 11 && sum != 12 && sum !=7 && sum != 2 && sum !=3)

    大兄弟 你短路了。。。

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 数学的三元一次方程求解
  • ¥20 iqoo11 如何下载安装工程模式
  • ¥15 本题的答案是不是有问题
  • ¥15 关于#r语言#的问题:(svydesign)为什么在一个大的数据集中抽取了一个小数据集
  • ¥15 C++使用Gunplot
  • ¥15 这个电路是如何实现路灯控制器的,原理是什么,怎么求解灯亮起后熄灭的时间如图?
  • ¥15 matlab数字图像处理频率域滤波
  • ¥15 在abaqus做了二维正交切削模型,给刀具添加了超声振动条件后输出切削力为什么比普通切削增大这么多
  • ¥15 ELGamal和paillier计算效率谁快?
  • ¥15 蓝桥杯单片机第十三届第一场,整点继电器吸合,5s后断开出现了问题