c++用成员函数和友元函数实现复数的加减操作，产生了二义性，麻烦各位大哥大姐解答一下，感激不尽

Question

我想在一个程序中用友元函数和类的成员函数实现复数的加减操作，
类中这样定义：

main函数中用这几句调用的话存在二义性：

c3=c1+c2;这一句就不知道到底该调用成员函数还是调用友元函数，但是重载的话只有参数类型和参数个数不同，就应该没问题的，这里该怎么解决呢？
麻烦各位大哥大姐了；下面是程序的代码，

#include

class Complex
{
public:
Complex(double r=0.0,double i=0.0):real(r),imag(i){}
Complex operator+ (const Complex &c2)const;
Complex operator- (const Complex &c2)const;

    friend Complex operator+(const Complex &c1,const Complex &c2);
    friend Complex operator-(const Complex &c1,const Complex &c2);


    friend ostream &operator<< (ostream &out,const Complex &c);
    void display()const;
private:
    double real;
    double imag;            

} ;

Complex Complex::operator+ (const Complex &c2)const
{
return Complex(real+c2.real,imag+c2.imag);
}
Complex Complex::operator- (const Complex &c2)const
{
return Complex(real-c2.real,imag-c2.imag);
}

void Complex::display()const
{
cout<<"("<<real<<","<<imag<<")"<<endl;
}

Complex operator+(const Complex &c1,const Complex &c2)
{
return Complex(c1.real+c2.real,c1.imag+c2.imag);
}
Complex operator-(const Complex &c1,const Complex &c2)
{
return Complex(c1.real-c2.real,c1.imag-c2.imag);
}
ostream &operator<< (ostream &out,const Complex &c)
{
out<<"("<<c.real<<","<<c.imag<<")"<<endl;
return out;
}

int main()
{
Complex c1(5,4),c2(2,10),c3;
c1.display();
c2.display();
c3.display();

c3=c1+c2;
c3.display();
cout<<c3;

c3=c3-c1;
c3.display();
cout<<c3;

return 0;

}

Answer 1

你在函数里写个输出就能看出优先级了，具体我也没试过，无法给出正确答案