lwjjiayou 2015-11-29 06:35 采纳率: 0%
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C语言 这道题怎解 似乎并不难

Description

Lasercat numbers are defined recursively as follows.
(1) numbers 1 and 2 are Lasercat numbers;
(2) if a and b are Lasercat numbers, so is (a+b)^2-1;
(3) only the numbers defined in (1) and (2) are Lasercat numbers.
Now your task is to judge whether an integer is a Lasercat number.

Input

There are several lines in input. The first line of the input is the number of the cases, the next each line has a non-negative integer a, 0<=a<=1000000000.

Output

For the number a on each line of the input, if a is a Lasercat number, output “YES!”, otherwise output “NO!”.

Sample Input
2
3
14

Sample Output
YES!
NO!

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  • 紫气天堂 2015-11-29 07:29
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