讲的详细点,我是大一新生,小白,尽可能把调试好的代码发一遍

6条回答 默认 最新
i_dontknow 2015-12-07 12:33关注#include
int f(int,int);
int power(int, int);int main()
{
int k,n;std::cout << "please input n:"; std::cin >> n; std::cout << "please input k:"; std::cin >> k; std::cout << "result = " << f(n,k) << std::endl; return 0;}
// 1^k + 2^k + 3^k + ... + n^k
int f(int n, int k)
{
int sum = 0;
for (int i = 1; i <= n; ++i)
{
sum = sum + power(i, k);
}
return sum;
}// m^n
int power(int m, int n)
{
int product = 1;
for (int i = 0; i < n; ++i)
{
product = product * m;
}
return product;
}本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报