关于字符型指针数组的理解问题

Question

#include<stdio.h>
main()
{

    char *name[]={"zhang","gou","xu","zheng","mao","zhao","li","bai","qing"};
    printf("%s\n",*name[1]);
}

此时程序无运行结果。而去掉name前的*之后运行结果正确，为“gou”，请问该如何理解字符型指针数组，name[1]难道不是一个指针吗？它的值不是应该为地址吗？该如何理解呢？

 #include<stdio.h>
main()
{

    char *name[]={"zhang","gou","xu","zheng","mao","zhao","li","bai","qing"};
    printf("%s\n",name[1]);
}

Answer 1

char *name[]; //定义了指针数组，每一个元素是一个字符指针变量，被分别初始化为各个字符串的起始地址。
printf中%s需要一个字符串的地址，所以name[1]就是，是“gou”的起始地址。