hdu1003 主要是java中的printf和print 2C
package hdu;

import java.math.BigInteger;
import java.util.Scanner;
public class hdu1003 {
    public static void main(String[] args){
        Scanner cin=new Scanner(System.in);
        int n=cin.nextInt();
        for(int i=1;i<=n;i++){
            BigInteger a=cin.nextBigInteger();
            BigInteger b=cin.nextBigInteger();
            BigInteger c=a.add(b);
            System.out.println("Case"+" "+i+":");
            System.out.println(a+" + "+b+" = "+c);
            /*
       *System.out.printf("Case %d:\n",i);
             *System.out.printf("%d + %d = %d\n",a,b,c);
       *这种提交结果是presentation error  为什么呢?
             *我在加号和等号两边也加了一个空格的啊
            */
            if(i<n) System.out.println();

        }

        cin.close();
    }

}


题目是:
就是两个大数相加
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input
2
1 2
112233445566778899 998877665544332211

Sample Output
Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

1个回答

题意没有描述清楚,不知道你到底表达什么意思,是有报错吗?

IhaveNoKickName
cawsl 谢谢了帮我看看
4 年多之前 回复
IhaveNoKickName
cawsl 嗯嗯 是presentation error .但是我觉得两种表达方式是一样的.可是用我注释掉的那一种就是过不了
4 年多之前 回复
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