- 链表中的节点的数据域可以直接插入结构体吗？打印时要怎么写呢？
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链表中的节点的数据域可以直接插入结构体吗？如下：
struct student { int num; char name[10]; int grade; }; struct stunode { struct student; struct stunode * next; };如果这样可以的话，打印时要怎样写呢？（见最后几行，事实证明这样写是不可能成功的。。。）求指点
#include<stdio.h> #include<stdlib.h> struct student { int num; char name[10]; int grade; }; struct stunode { struct student; struct stunode * next; }; main() { int i; struct stunode *p,*head; struct student h[13]= { {2,"Lin",92}, {3,"Zhang",87}, {4,"Zhao",72}, {5,"Ma",91}, {9,"Zhen",85}, {11,"Wang",100}, {12,"Li",86}, {13,"Xu",83}, {16,"Mao",78}, {17,"Hao",95}, {20,"Lu",82}, {21,"Song",76}, {22,"Wu",88} }; head=NULL; for(i=0;i<13;i++) { p=(struct stunode *)malloc(sizeof(struct stunode)); p->next=head; p->stu=h[i]; head=p; } for(i=1;i<=12;i++) { printf("%d %s %f\n",head->stu); head++; } printf("%d %s %f\n",head->stu); }还有一个问题：数组节点是什么意思？
struct student
{
int num;
char name[10];
int grade;
};
struct stunode
{
struct student stu;
struct stunode * next;
};
int main()
{
int i;
struct stunode *p,*head;
struct student h[13]=
{
{2,"Lin",92},
{3,"Zhang",87},
{4,"Zhao",72},
{5,"Ma",91},
{9,"Zhen",85},
{11,"Wang",100},
{12,"Li",86},
{13,"Xu",83},
{16,"Mao",78},
{17,"Hao",95},
{20,"Lu",82},
{21,"Song",76},
{22,"Wu",88}
};
head=NULL;
for(i=0;i
{
p=(struct stunode *)malloc(sizeof(struct stunode));
p->next=head;
p->stu=h[i];
head=p;
}
for(i=1;i<=12;i++)
{
printf("%d %s %d\n",head->stu.num, head->stu.name, head->stu.grade);
head = head->next;
}
printf("%d %s %d\n",head->stu.num, head->stu.name, head->stu.grade);
}
struct stunode
{
struct student;
struct stunode * next;
};
你这里错了啊！当然不行了。struct student; 这两个联合起来是一个定义，但是你的变量声明呢？
麻烦改成：
struct stunode
{
struct student myStudent;
struct stunode * next;
};
