androidSocket通信TCP接收数据问题

Question

rivate Button send;
private TextView rec;
private static Socket client;
private PrintWriter write;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
rec=(TextView)findViewById(R.id.textView3);;
Thread aa=new Thread(new Runnable() {

            @Override
            public void run() {
                // TODO Auto-generated method stub
                 try {
                     //服务器的ip的地址 和端口号
                        client=new Socket(InetAddress.getByName("192.168.1.101"),4312);
                        BufferedReader read=new BufferedReader
                        (new InputStreamReader(client .getInputStream()));                                                      

                        rec.setText("123");                        
                     String  s = "";

                 while(true){
                        s=read.readLine();
                      rec.setText(s);
                     }

                  }

                    catch(IOException e){ 
                        rec.setText("123123");
                    }   

            }
        });
          aa.start();
    ｝
在  while(true){ s=read.readLine(); rec.setText(s); }为什么只能接收服务器的一次消息第二次手机就会跳出程序

Answer 1

要考虑没有收到数据时，要怎么处理