关于cout对函数输出的问题

Question

#if 1
#include
#include
using namespace std;
string::size_type find_char(const string &s, char c, string::size_type &occurs)
{
auto ret = s.size();
occurs = 0;
for (decltype(ret)i = 0; i != s.size(); ++i){
if (s[i] == c){
if (ret == s.size())
ret = i;
++occurs;
}
}
return ret;
}
int main(){
string a("ewusruywsoieuyruwaufbnsdbyfeywaryawiuruaiwhruwhfadsfsf");
char b = 's';
string::size_type m = 0;
/*此处之所以输出的m为最初定义时候的值*/
//cout << find_char(a, b, m) << '\n' << m << endl;

auto s = find_char(a, b, m);
cout << s << '\n' << m << endl;

return 0;

}
#endif

Answer 1

你的具体问题是什么呢