c++中运算符重载 这个小程序怎么不对呢

Question

#include
using namespace std;

class R{
public :
int n;
int d;

R(int a,int b)
{
    this->n=a;
    this->d=b;
}

};

ostream operator<< (ostream &os,R &r)
{
// os<<r.n<<endl;
// os<<r.d<<endl;;

os<<r.n<<','<<r.d;
return os; //此处报错了 在vs2015中做的
}

int main()
{

R a(2,3),b(4,5);
cout<<a<<b;
return 0;

}

Answer 1

这是我写的一个重载输入输出去处符的小例子, 你参考一下吧

class Test

{
public:
    int a;
    int b;
    Test():a(0),b(0){}
    Test(int a, int b):a(a),b(b){}
    //重载输入输出运算符，只能用友元函数
    friend ostream &operator<<(ostream &os, const Test &T);
    friend istream &operator>>(istream &is, Test &T);
};

ostream &operator<<(ostream &os, const Test &T)
{
    os << "a = " << T.a << endl;
    os << "b = " << T.b << endl;

    return os;
}

istream &operator>>(istream &is, Test &T)
{
    is >> T.a >> T.b;
    return is;
}