yuan.cpp
i:\数据结构课程设计\yiyuanduoxiangshi\yuan.cpp(2) : error C2143: syntax error : missing ';' before 'PCH creation point'
i:\数据结构课程设计\yiyuanduoxiangshi\yuan.cpp(5) : error C2143: syntax error : missing ';' before 'PCH creation point'
i:\数据结构课程设计\yiyuanduoxiangshi\yuan.cpp(6) : error C2143: syntax error : missing ';' before '{'
i:\数据结构课程设计\yiyuanduoxiangshi\yuan.cpp(7) : error C2143: syntax error : missing ';' before 'PCH creation point'
i:\数据结构课程设计\yiyuanduoxiangshi\yuan.cpp(8) : error C2143: syntax error : missing ';' before 'PCH creation point'
i:\数据结构课程设计\yiyuanduoxiangshi\yuan.cpp(9) : error C2143: syntax error : missing ';' before 'PCH creation point'
i:\数据结构课程设计\yiyuanduoxiangshi\yuan.cpp(10) : error C2143: syntax error : missing ';' before 'PCH creation point'
i:\数据结构课程设计\yiyuanduoxiangshi\yuan.cpp(11) : fatal error C1004: unexpected end of file found

yiyuanduoxiangshi.exe - 1 error(s), 0 warning(s)

#include<iostream>
using namespace std;
float sum;

typedef struct PNode
{
float coef;
int expn;
struct PNode *next;
}PNode, *Polynomial;

void CreatePolyn(Polynomial &P,int n)
{//输入m项的系数和指数，建立表示多项式的有序链表P
P = new PNode;
P->next = NULL;
int i;
Polynomial s,pre,q;
for( i=1; i<=n; ++i )
{
s = new PNode;
cout<<"请输入系数和指数："<<endl;
cin>>s->coef>>s->expn;
pre = P;                        // pre用于保存q的前驱，初值为头结点
q = P->next;                    // *q为第一个大于输入项指数的节点
while( q && q->expn<s->expn )
{
pre = q;
q = q->next;
}
s->next = q;
pre->next = s;
}
}

{//多项式加法：Pa=Pa+Pb，利用两个多项式的节点构成和多项式
Polynomial p1,p2,p3,r;

p1 = Pa->next;  p2 = Pb->next;      //p1和p2初值分别指向Pa和Pb的首元结点
p3 = Pa;                            //p3指向和多项式的当前节点，初值为Pa
while( p1 && p2 )                   //p1和p2均非空
{
if( p1->expn == p2->expn )      //指数相等
{
sum = p1->coef + p2->coef;      //sum保存两项的系数和
if( sum!=0 )                    //系数和不为零
{
p1->coef = sum;                     //修改Pa当前节点的系数值为两项系数的和
p3->next = p1;  p3 = p1;            //将修改后的Pa当前节点链在p3之后，p3指向p1
p1 = p1->next;                      //p1指向后一项
r = p2; p2 = p2->next; delete r;    //删除Pb当前节点，p2指向后一项
}
else                                    //系数和为零
{
r = p1; p1 = p1->next;  delete r;
r = p2; p2 = p2->next;  delete r;
}
}
else if( p1->expn < p2->expn )  //Pa当前节点的指数值小
{
p3->next = p1;
p3 = p1;
p1 = p1->next;
}
else                            //Pb当前节点的指数值小
{
p3->next = p2;
p3 = p2;
p2 = p2->next;
}
}
p3->next = p1?p1:p2;                //插入非空多项式的剩余段
delete Pb;
}

void Output(Polynomial &Pa)
{
Polynomial p;   //p用来指向当前节点
p = Pa->next;
cout<<"相加后的多项式为："<<endl;
while ( p->next!=NULL )
{
cout<<p->coef<<"x^"<<p->expn<<"+";
p = p->next;
}
cout<<p->coef<<"x^"<<p->expn<<endl;
}

void Userface()
{
cout<<"           欢迎使用一元多项式加法器！              "<<endl;
cout<<"---------------------------------------------      "<<endl;
//  cout<<"-                                           -      "<<endl;
cout<<"-                                           -      "<<endl;
cout<<"-                 1.计算                    -      "<<endl;
cout<<"-                 2.退出                    -      "<<endl;
cout<<"-                                           -      "<<endl;
//  cout<<"-                                           -      "<<endl;
cout<<"---------------------------------------------      "<<endl;
cout<<"请输入序号选择您需要的功能："<<endl;

}

void Jisuan()
{
int n;
cout<<"请输入第一个多项式项数："<<endl;
cin>>n;
Polynomial Pa;
CreatePolyn(Pa,n);
cout<<"请输入第二个多项式项数："<<endl;
cin>>n;
Polynomial Pb;
CreatePolyn(Pb,n);
Output(Pa);
}

void Select()
{
int k;
cin>>k;
switch(k)
{
case 1: Jisuan();
break;
case 2: exit(1);
default:
cout<<"输入错误，请重新输入："<<endl;
Userface();
Select();
break;
}
#include<iostream>
#include"Status.h"
using namespace std;

int main()
{
Userface();
Select();
return 0;
}

3个回答

void Select()定义中switch少后括号

c);} b a &c); if(a%d>%d" &b &a c/n"); scanf("%d%d%d" b t; printf("input a c b z);}|||#includemain(){ int a y x y的值*/ printf("small to big: %d %d %d/n" z的值*/ if(y答案就在这里：请教一个C语言问题
----------------------Hi，地球人，我是问答机器人小S，上面的内容就是我狂拽酷炫叼炸天的答案，除了赞同，你还有别的选择吗？

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