login.jsp跳到log_login.do，无论用户名和密码输入什么都提示用户名或密码不正确

Question

LoginoutAction.java
package com.bfmd.xj.action;

import javax.servlet.http.HttpSession;

import org.apache.struts2.ServletActionContext;

import com.bfmd.xj.bean.User;
import com.bfmd.xj.service.LoginoutService;
import com.opensymphony.xwork2.ActionSupport;

public class LoginoutAction extends ActionSupport{

private LoginoutService loginoutService;

private User user;

@SuppressWarnings("unchecked")
public String login() {


    boolean isHaveUser = false;

    try {
        isHaveUser = loginoutService.ifHave(user);
    } catch (Exception e) {
        e.printStackTrace();
    }

    if (isHaveUser) {

        HttpSession session = ServletActionContext.getRequest().getSession();

        session.setAttribute("identity", user.getStudent_id());

        if (user.getIdentity().equals("a")) {
            return "admin";
        }

        if (user.getIdentity().equals("s")) {
            return "student";
        }

        if (user.getIdentity().equals("t")) {
            return "teacher";
        }
    }else{
        addActionError("用户名或密码错误");
    }

    return "login";
}

public String logout(){

    HttpSession session = ServletActionContext.getRequest().getSession(false);

    if(session != null){
        session.removeAttribute("identity");
    }

    return "login";
}

public LoginoutService getLoginoutService() {
    return loginoutService;
}



public void setLoginoutService(LoginoutService loginoutService) {
    this.loginoutService = loginoutService;
}

public User getUser() {
    return user;
}

public void setUser(User user) {
    this.user = user;
}

}

Answer 1

action.LoginoutAction中login（）的方法应该有问题